When formic aldehyde is oxidized with silver oxide, 2 g of metallic silver is formed.

When formic aldehyde is oxidized with silver oxide, 2 g of metallic silver is formed. What mass of aldehyde has oxidized?

Let’s write down the solution:
1. НСОН + Ag2O = 2Ag + HCOOH – the oxidation reaction of aldehyde with silver oxide, silver and formic acid are released;
2. Let’s define the molar masses of substances:
M (CH2O) = 12 + 2 + 16 = 30 g / mol;
M (Ag) = 107.8 g / mol;
3. Let’s calculate the number of moles of silver, if its mass is known:
Y (Ag) = m / M = 2 / 107.8 = 0.019 mol;
4. We make the proportion according to the data of the reaction equation:
X mol (CH2O) – 0.019 mol (Ag);
-1 mol – 2 mol from here, X mol (Ag) = 1 * 0.019 / 2 = 0.0095 mol;
5. Determine the mass of formic aldehyde by the formula:
m = Y * M = 0.0095 * 30 = 0.28 g.
Answer: The reaction requires 0.28 g of formic aldehyde.