When gasoline is burned in a car engine, 12 MJ of energy was released in 1 minute, the average engine power

When gasoline is burned in a car engine, 12 MJ of energy was released in 1 minute, the average engine power being equal to 48 kW. Determine the efficiency of the motor.

Initial data: t (duration of gasoline combustion in a car engine) = 1 min (60 s); Q (released amount of energy) = 12 MJ (12 * 10 ^ 6 J); Np (average power of a car engine) = 48 kW (48 * 10 ^ 3 W).

The efficiency of the engine can be determined by the formula: η = Nп / Nз = Nп / (Q / t) = Nп * t / Q.

Calculation: η = 48 * 10 ^ 3 * 60 / (12 * 10 ^ 6) = 0.24 (24%).

Answer: The efficiency of a car engine is 24%.



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