When gasoline was burned in a car engine, 1200 kJ of energy was released in 2 s

When gasoline was burned in a car engine, 1200 kJ of energy was released in 2 seconds, while the engine did 300 kJ of useful work. What is the useful engine power?

To find out the net power of the specified automobile engine, consider the formula: Npol = Apol / t, where Apol is the total useful work of the specified automobile engine (Apol = 300 kJ = 3 * 10 ^ 5 J); t – duration of operation, gasoline combustion (t = 2 s).

Let’s perform the calculation: Npol = Apol / t = 3 * 10 ^ 5/2 = 1.5 * 10 ^ 5 W.

Answer: The power of the indicated car engine, according to the calculation, is 150 kW.