When hanging the load, the spring stretched 6 cm. Determine what is the weight of the load if the spring rate is 50n / m?

x = 6 cm = 0.06 m.

k = 50 N / m.

g = 10 m / s2.

m -?

The condition for finding a body in a state of balance on a spring is the balancing of all the forces that act on it. The suspended load is acted upon by 2 forces: the force of gravity Ft directed vertically downward, and the force of elasticity of the spring Ffr directed vertically upward.

Fт = Fпр – the condition of the balance of the load.

The force of gravity that acts on the load is expressed by the formula: Ft = m * g.

We express the elastic force according to Hooke’s law: Fel = k * x.

m * g = k * x.

m = k * x / g.

m = 50 N / m * 0.06 m / 10 m / s2 = 0.3 kg.

Answer: the load has a mass of m = 0.3 kg.