When heated on an alcohol lamp, 290 g of water taken at room temperature, 2 g of alcohol were consumed.

| July 7, 2021 | education

When heated on an alcohol lamp, 290 g of water taken at room temperature, 2 g of alcohol were consumed. How many degrees has the water heated, if we assume that all the energy released during the combustion of alcohol goes to heating the water?

Data: mw (mass of water heated on an alcohol lamp) = 290 g (in SI mw = 0.29 kg); mc (mass of consumed alcohol) = 2 g (in SI mc = 0.002 kg); no heat loss.

Constants: q (specific heat of combustion of alcohol) = 2.7 * 10 ^ 7 J / kg; C (specific heat of water) = 4200 J / (kg * K).

The desired increase in water temperature is determined from the equality: C * mw * Δt = q * mc, whence Δt = q * mc / (C * mw).

Calculation: Δt = 2.7 * 10 ^ 7 * 0.002 / (4200 * 0.29) = 44.3 ºС.

Answer: The water was heated by 44.3 ºС.



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