When heating Berthollet salt KClO₃, it decomposes: 2KClO₃ → 2KCl + 3O₂ ↑. Calculate the volume of oxygen

When heating Berthollet salt KClO₃, it decomposes: 2KClO₃ → 2KCl + 3O₂ ↑. Calculate the volume of oxygen that will be released during the decomposition of 12.25 g of berthollet’s salt. What mass of potassium chloride is formed in this case?

2KClO3 = 2KCl + 3O2 – OBP, oxygen, potassium chloride are evolved;
Calculations:
M (KClO3) = 122.6 g / mol;

M (KCl) = 74.6 g / mol;

Y (KClO3) = m / M = 12.25 / 122.6 = 0.09 mol;

Y (KCl) = 0.09 mol since the amount of substances is 2 mol.

Determine the mass of salt:
m (KCl) = Y / M = 0.09 * 74.6 = 6.7 g.

Proportion:
0.09 mol (KClO3) – X mol (O2);

-2 mol – 3 mol from here, X mol (O2) = 0.09 * 3/2 = 0.135 mol.

We find the volume of O2:
V (O2) = 0.135 * 22.4 = 3.024 L

Answer: oxygen was obtained with a volume of 3.024 l, potassium chloride with a mass of 6.7 g