When immersed in water, the body decreases in weight by 5 times. Determine the density of the body.
| June 23, 2021 | education
Data: P (weight in air) = 5Pw (weight in water); ρw (water density) = 1000 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.
To determine the density of the specified body, we use the equality: P = 5Pv.
m * g = 5 * (m * g – ρw * g * V).
ρt * V = 5 * (ρt * V – ρw * V).
ρт = 5 (ρт – ρв).
ρт = 5 ρт – 5ρв.
ρt = 5ρw / 4 = 5 * 1000/4 = 1250 kg / m3.
Answer: The density of the specified body is 1250 kg / m3.
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