When immersed in water, the iron anchor becomes lighter by 120 N. Determine the volume of the anchor

When immersed in water, the iron anchor becomes lighter by 120 N. Determine the volume of the anchor and its weight in the water.

The difference between the weight of the anchor in air and in water will be equal to the Archimedes force:
Then: Fa = ρw * g * V = 120 N, where ρw is the density of water (ρ = 1000 kg / m ^ 3), g is the acceleration of gravity (g = 10 m / s ^ 2), V is the volume of the armature.
V = Fa / ρw * g = 120 / (1000 * 10) = 0.012 m ^ 3.
m = ρzh * V, where ρzh is the density of iron (ρzh = 787 kg / m ^ 3)
m = 7874 * 0.012 = 94.448 kg.
Anchor weight in the air:
P = Ft = m * g = 94.448 * 10 = 944.48 N.
Anchor weight in water: Ft – Fа = 944.48 – 120 = 824.48 N.
Answer. Anchor volume 0.012 m ^ 3, Weight in water 824.48 N.