When interacting, the oxide of the two valence metal mass = 11, 2g. hydroxide with a mass of 14 8 g is formed with water. Find metal.

univerkov | December 3, 2020 | education

MeO + H2O = Me (OH) 2
m (H2O) = m (Me (OH) 2) -m (MeO) = 14.8-11.2 = 3.6 g
n (H2O) = m \ M = 3.6 \ 18 = 0.2 mol
n (MeO) = n (H2O) = 0.2 mol at ur-th p-i
M (MeO) = m \ n = 11.2 \ 0.2 = 56 g \ mol
M (Me) = 56-M (O) = 56-16 = 40 g / mol
Answer: Ca

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