When interacting with an acid, 13.07 g of a divalent metal displace 4.48 liters of hydrogen.

| September 2, 2021 | education

When interacting with an acid, 13.07 g of a divalent metal displace 4.48 liters of hydrogen. Calculate the molar mass of the metal equivalent.

The weight of the divalent metal is 13.07 g;
The volume of displaced hydrogen is 4.48 liters.
Find the molar mass of the metal equivalent.
We use the following formula.
n (H2) = V / Vm.
n (H2) = 4.48 L / 22.4 L / mol = 0.2 mol.
Where n is the amount of substance, V is the volume of the substance, Vm is the molar volume equal to 22.4 l / mol.
Since the hydrogen atom is monovalent, and the metal atom is divalent, it means that 1 metal atom will displace 2 hydrogen atoms, which means it turns out.
n (Me) = n (H2) = 0.2 mol.
Find the molar mass of the equivalent.
n = m / M.
M = m / n.
M = 13.07 g / 0.2 = 65.35 g / mol.
This means that this metal is zinc.
Answer: M = 65.35 g / mol.



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