When it cooled down by 15 ° C, the body lost an amount of heat equal to 2500 J.
| May 21, 2021 | education
When it cooled down by 15 ° C, the body lost an amount of heat equal to 2500 J. How much heat will it lose by cooling to 45 ° C?
Initial data: Δt1 (initial change in body temperature) = 15 ºС; Q1 (heat loss by the body during initial cooling) = 2500 J; Δt2 (final change in body temperature) = 45 ºС.
The loss of heat by the body during cooling by 45 ºС is determined using the equality (Q = C * m * Δt): С * m = Q1 / Δt1 = Q2 / Δt2, whence Q2 = Q1 * Δt2 / Δt1.
Calculation: Q2 = 2500 * 45/15 = 7500 J.
Answer: When it cools down to 45 ºС, the body will lose 7500 J of heat.
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