When lifting a body weighing 5 kg to a certain height, work of 500 J was performed.

When lifting a body weighing 5 kg to a certain height, work of 500 J was performed. Determine the height of the body.

Task data: m (weight of the lifted body) = 5 kg; A (work done during lifting, change in potential energy) = 500 J.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

We express the sought-for height of the body’s rise from the formula: A = ΔEp = m * g * h, whence h = A / (m * g).

Let’s calculate: h = 500 / (5 * 10) = 10 m.

Answer: The body was raised to a height of 5 m.