When lifting a load of 2T, a work of 200 kJ was performed. What height does the load reach?

Initial data: m (mass of the lifted load) = 2 t (2000 kg); A (work done while lifting the load) = 200 kJ (200 * 10 ^ 3 J).

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The height to which the load was lifted is determined from the formula for calculating the mechanical work: A = ΔEp = m * g * Δh, whence Δh = A / (m * g).

Let’s calculate: Δh = 200 * 10 ^ 3 / (2000 * 10) = 10 m.

Answer: The load was lifted to a height of 10 meters.