When lifting a load weighing 140 N using a movable block, a force of 76 N. was applied to the rope.
| February 5, 2021 | education
When lifting a load weighing 140 N using a movable block, a force of 76 N. was applied to the rope. What is the weight of the block? calculate the efficiency of the installation if the load needs to be lifted to a height of 6 m.
Task data: Pg (weight of the load) = 140 N; F (the force with which the rope was pulled) = 76 N; h (height to which you want to lift the load) = 6 m; the load is lifted with a movable block.
1) Determine the weight of the movable unit: F = 0.5Pg + Pb and Pb = F – 0.5Pg = 76 – 0.5 * 140 = 6 N.
2) Let’s calculate the efficiency of the installation: η = ΔEp / Az = Pg * h / (F * 2h) = Pg / 2F = 140 / (2 * 76) = 0.921 (92.1%).
Answer: The weight of the block is 6 N; The plant efficiency is 92.1%.
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