When lifting a load weighing 140N using a movable block, they acted on the rope with a force of 76 N.

When lifting a load weighing 140N using a movable block, they acted on the rope with a force of 76 N. What is the weight of the block?

Initial data: Pg (weight of the lifted load) = 140 N; F (force with which they acted on the rope) = 76 N; the load was lifted using a movable block.

We express the weight of the movable block from the equality: F = 0.5Pg + Pb, whence Pb = F – 0.5Pg.

Calculation: Pb = 76 – 0.5 * 140 = 6 N.

Answer: The weight of the movable block is 6 N.



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