When magnesium interacted with 9.8 g of sulfuric acid, 1.68 liters of hydrogen were released.

When magnesium interacted with 9.8 g of sulfuric acid, 1.68 liters of hydrogen were released. Determine the volume fraction of the gas outlet.

Magnesium dissolves in sulfuric acid solution. The reaction is described by the following chemical equation:

Mg + H2SO4 = MgSO4 + H2 ↑;

Let’s calculate the molar amount of sulfuric acid.

To do this, divide its weight by the weight of 1 mole of acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 9.8 / 98 = 0.1 mol;

The same amount of hydrogen will be produced.

Let’s determine the volume of hydrogen.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 0.1 x 22.4 = 2.24 liters;

The reaction yield will be: 1.68 / 2.24 = 0.75 = 75%;