When magnesium interacts with sulfuric acid, 2.24 liters of hydrogen were released.

When magnesium interacts with sulfuric acid, 2.24 liters of hydrogen were released. Determine the mass of reacted magnesium.

Given:
V (H2) = 2.24 L

To find:
m (Mg) -?

Decision:
1) Write the equation of a chemical reaction:
Mg + H2SO4 => MgSO4 + H2 ↑;
2) Using the periodic system of D.I.Mendeleev, calculate the molar mass of Mg:
M (Mg) = Mr (Mg) = Ar (Mg) = 24 g / mol;
3) Calculate the amount of substance H2:
n (H2) = V (H2) / Vm = 2.24 / 22.4 = 0.1 mol;
4) Determine the amount of Mg substance (taking into account the coefficients in the reaction equation):
n (Mg) = n (H2) = 0.1 mol;
5) Calculate the mass of Mg:
m (Mg) = n (Mg) * M (Mg) = 0.1 * 24 = 2.4 g.

Answer: The mass of Mg is 2.4 g.