When magnesium silicide is acted upon by hydrochloric acid, a silane is formed. Write down the equation
When magnesium silicide is acted upon by hydrochloric acid, a silane is formed. Write down the equation for the reaction of obtaining and igniting silane and calculate how much air will be required to burn 12 liters of silane.
Mg2Si + 2HCl = MgCl2 + SiH4.
SiH4 + 2O2 = SiO2 + 2H2O.
Let’s find the amount of substance SiH4.
n = V: Vn.
n = 12 L: 22.4 L / mol = 0.536 mol.
There are 2 mol of O2 per mole. Substances are in quantitative ratios 1: 2. The amount of substance O2 is 2 times greater than SiH4.
n (О2) = 2n (SiH4) = 0.536 × 2 = 1.072 mol.
Find the volume of O2.
V = n Vn, where Vn is the molar volume of the gas equal to 22.4 l / mol.
V = 1.072 mol × 22.4 L / mol = 24.01 L.
24.01 – 21%,
X- 100%,
X = (24.01 × 100%): 21% = 114.33 liters.
Answer: 114.33 liters.