When making shot, water is poured into lead with a temperature of 327 degrees.

When making shot, water is poured into lead with a temperature of 327 degrees. What amount of shot was made if 3 liters of water was heated at the same time from 25 to 47 degrees C?

Data: t1 (temperature of lead) = 327 ºС; V (water volume) = 3 l (m2 = 3 kg); t2 (water temperature) = 25 ºС; t (equilibrium temp.) = 47 ºС.

Constants: λ (beats heat of crystallization of lead) = 0.25 * 10 ^ 5 J / kg; Cc (specific heat capacity of lead) = 140 J / (kg * K); Sv (specific heat capacity of water) = 4200 J / (kg * K).

We express the mass of the fraction from the equality: m1 * (λ + Cc * (t1 – t)) = Sv * m2 * (t1 – t) and m1 = Sv * m2 * (t1 – t) / (λ + Cc * (t1 – t)).

Calculation: m1 = 4200 * 3 * (47 – 25) / (0.25 * 10 ^ 5 + 140 * (327 – 47)) = 4.32 kg.