When measuring the specific heat of aluminum, a sample with a mass of 100 g was heated in boiling

When measuring the specific heat of aluminum, a sample with a mass of 100 g was heated in boiling water and then immersed in 100 g of water at a temperature of 20 ° C. As a result of heat exchange, a temperature of 35 ° C was established. What is the specific heat of aluminum? The specific heat capacity of water is 4200 J / (kg • K). Disregard heat loss.

Given: ma (mass of the aluminum sample) = 100 g (ma = 0.1 kg); t1 (initial sample temperature) = 100 ºС; mw (mass of water) = 100 g (mw = 0.1 kg); t2 (initial water temperature) = 20 ºС; t (temperature after heat exchange) = 35 ºС.

Constants: Sv (specific heat capacity of water) = 4200 J / (kg * K).

To calculate the heat capacity of aluminum, we use the equality: Ca * ma * (t1 – t) = Cw * mw * (t – t2) and Ca = Cw * mw * (t – t2) / (ma * (t1 – t)).

Calculation: Ca = 4200 * 0.1 * (35 – 20) / (0.1 * (100 – 35)) ≈ 969.2 J / (kg * K).