When Mg burns in oxygen, magnesium oxide is formed m 16 g, calculate the amount of oxygen

When Mg burns in oxygen, magnesium oxide is formed m 16 g, calculate the amount of oxygen substance that has reacted.

Magnesium is oxidized very intensively by oxygen. The oxidation reaction is described by the following equation:

Mg + ½ O2 = MgO;

During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.

Let’s determine the molar amount of magnesium oxide.

To do this, divide the available weight of magnesium oxide by the weight of 1 mole of this substance.

M MgO = 24 + 16 = 40 grams / mol; N MgO = 16/40 = 0.4 mol;

To burn this amount of magnesium, 2 times less chemical (molar) amount of oxygen is required. The amount of oxygen substance will be 0.666 / 2 = 0.333 mol;

Let’s find its weight.

Let’s multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol; m O2 = 0.4 / 2 x 32 = 6.4 grams;