When moving on the section of the charge circuit of 2 C, the electric field did the work of 80 J.

When moving on the section of the charge circuit of 2 C, the electric field did the work of 80 J. Find the voltage in this section.

Answer: 40 V.
Explanation of the solution:
to solve this problem, it is necessary to use the formula: U = A / q, where U is the voltage at the ends of the section in V, A is the work of the electric field to move the charge from one point of the field to another in J, q is the charge in Cl.
Substituting the values specified in the problem statement, we obtain: U = A / q = 80 J / 2 Kl = 40 V.