When phosphorus burns in an excess of oxygen, a substance P2O5 is formed, make an equation

When phosphorus burns in an excess of oxygen, a substance P2O5 is formed, make an equation for this chemical reaction, calculate the mass of burnt phosphorus, if P2O5 with a mass of 14.2 g is formed

The reaction for the synthesis of pentavalent phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. In the course of the reaction, 2 molecules of pentavalent phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance contained in phosphorus oxide weighing 14.2 grams.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

N P2 O5 = 14.2 / 142 = 0.1 mol;

To synthesize such an amount of oxide, it is necessary to take 0.1 x 2 = 0.2 mol of phosphorus.

Let’s calculate its weight:

M P = 31 grams / mol;

m P = 0.2 x 31 = 6.2 grams;