When plowing, the tractor overcomes a drag force of 10 kN. Developing a speed of 3.6 km / h

When plowing, the tractor overcomes a drag force of 10 kN. Developing a speed of 3.6 km / h. What is the net power of the tractor?

Fcopr = 10 kN = 10000 N.

V = 3.6 km / h = 1 m / s.

Floor -?

Net tractor power Npol shows what kind of mechanical work A is performed by the tractor per unit of time t: Npol = Apol / t.

The useful work of the Apol tractor is determined by the formula: Apol = Ft * S, where Ft is the traction force of the tractor, S is the path traveled by the tractor when plowing the land.

Since the tractor moves uniformly, according to Newton’s 1 law, the traction force Ft of the tractor is equal to the resistance force Fcop: Ft = Fcop.

The ratio of the traversed path S to the time of its passage t is called the speed V: V = S / t.

Net tractor power Npol will be determined by the formula: Npol = Fcopr * S / t = Fcopr * V.

Npol = 10000 N * 1 m / s = 10000 W.

Answer: the useful power of the tractor when plowing is Npol = 10000 W = 10 kW.