When pouring solutions containing 1.6 g of copper sulfate (2) and 28 g of potassium hydroxide, forms a precipitate weighing (in g) _.

Given
m (CuSO4) = 1.6
m (KOH) = 28
m (draft) -?
Decision
1.Write the reaction equation and place the coefficients:
2KOH + CuSO4 = Cu (OH) 2 (precipitate) + K2SO4
2. find the amount of substances by the formula n = m / M, where n is the amount of a substance, m is the mass of a substance, M is the molar mass of a substance
n (KOH) = 28/56 = 0.5 mol
n (CuSO4) = 1.6 / 160 = 0.1 mol
Because CuSO4 is a disadvantage, then further calculations will be carried out on it.
3. Find the mass of a substance by the formula m = n * M, where m is the mass of the substance, n is the amount of the substance, M is the molar mass of the substance
m (Cu (OH) 2) = 0.1 * 98 = 9.8 g
Answer: sediment weight 9.8 g.