When reducing 8.8 g of acetaldehyde, 8.5 g of alcohol was obtained. What is the mass fraction of the alcohol

When reducing 8.8 g of acetaldehyde, 8.5 g of alcohol was obtained. What is the mass fraction of the alcohol yield from the theoretically possible?

CH3COH + H2 = CH3CH2OH
Let’s calculate the amount of aldehyde substance:
n = m / M = 8.8 grams / 44 grams / mol = 0.2 mol
According to the reaction equation:
n (CH3CH2OH) = n (CH3COH) = 0.2 mol
Let’s calculate the mass of 0.2 mol of alcohol:
m = n * M = 0.2 mol * 46 grams / mol = 9.2 grams – theoretical weight
Let’s calculate the reaction yield:
q = m (practical) / m (theory) * 100% = 8.5 grams / 9.2 grams * 100% = 92.4%