When sodium interacted with water, 2.8 liters of gas were released.

| February 2, 2021 | education

When sodium interacted with water, 2.8 liters of gas were released. Determine the amount of the substance and the mass of sodium that has reacted.

1. Let’s find the amount of gas substance – hydrogen.

V = Vn n, where Vn is the molar volume of gas equal to 22.4 l / mol, and n is the amount of substance.

n = V: Vn.

n = 2.8 L: 22.4 L / mol = 0.125 mol.

Let’s compose the reaction equation:

2 Na + 2H2O = 2 NaOH + H2.

According to the reaction equation, for 1 mole of hydrogen there are 2 moles of sodium, that is, the substances are in quantitative ratios 1: 2, which means the amount of sodium substance will be 2 times more than the amount of hydrogen substance.

n (Na) = 2n (H2) = 0, 125 × 2 = 0.25 mol.

Let’s find the mass of sodium.

m = n × M.

M (Na) = 23 g / mol.

m = 0.25 mol × 23 g / mol = 5.75 g.

Answer: 5.75 g.



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