When sodium interacted with water, 5.6 liters of hydrogen were released. How many grams of sodium hydroxide was formed?
January 31, 2021 | education
| Let’s find the amount of the substance hydrogen.
V = Vn n, where Vn is the molar volume of the gas, equal to 22.4 l / mol, and n is the amount of substance.
n = V: Vn.
n = 5.6 L: 22.4 L / mol = 0.25 mol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
2Na + 2H2O = 2NaOH + H2 ↑.
According to the reaction equation, there is 2 mol of sodium hydroxide for 1 mol of hydrogen. The substances are in quantitative ratios of 2: 1.
The amount of sodium hydroxide substance will be 2 times more than the amount of hydrogen substance.
n (NaOH) = 2n (H2) = 0.25 × 2 = 0.5 mol.
Find the mass of sodium hydroxide.
m = n × M.
M (NaOH) = 40 g / mol.
m = 40 g / mol × 0.5 mol = 20 g.
Answer: 20 g.
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