When starting from a standstill, the motorcycle at a distance of 402 m can reach a speed of 321.14 km / h.

| September 2, 2021 | education

When starting from a standstill, the motorcycle at a distance of 402 m can reach a speed of 321.14 km / h. With what average acceleration does it move? How long does it take to cover this distance?

V0 = 0 m / s.
V = 321.14 km / h = 89.2 m / s.
S = 402 m.
a -?
t -?
With uniformly accelerated motion, the acceleration of the body a is determined by the formula: a = (V ^ 2 – V0 ^ 2) / 2 * S. Where V, V0 is the final and initial speed of movement, S is the movement of the body during movement.
a = (89.2 m / s) ^ 2 – (0 m / s) ^ 2) / 2 * 402 m = 9.89 m / s ^ 2.
The acceleration time is expressed from the formula for acceleration: a = (V – V0) / t.
t = (V – V0) / a.
t = (89.2 m / s – 0 m / s) / 9.89 m / s ^ 2 = 9 s.
Answer: the motorcycle moves during acceleration with acceleration a = 9.89 m / s ^ 2, it lasts t = 9 s.



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