When sulfur (IV) oxide interacts with sodium hydroxide, sodium sulfite and water are formed

When sulfur (IV) oxide interacts with sodium hydroxide, sodium sulfite and water are formed: SO2 + 2NaOH → Na2SO3 + H2O Calculate how much sulfur (IV) oxide substance can react with 0.18 mol of sodium hydroxide.

Let’s write a reaction equation illustrating this chemical process:

SO2 + 2NaOH → Na2SO3 + H2O.

1 mol    2 mol          1 mol      1 mol

As can be seen from this reaction equation, sulfur (IV) oxide and sodium hydroxide react with each other in the ratio:

one molecule of sulfur (IV) oxide for 2 molecules of sodium hydroxide.

That is, in order for these substances to react completely, they must be taken in a quantitative ratio of 1: 2.

Therefore, we can make up the proportion:

1: 2 = x: 0.18.

x = 0.18: 2 = 0.09 (mol) sulfur oxide (IV).