When sulfuric acid was added with a mass fraction of 5% of excess barium nitrate solution, a precipitate weighing

When sulfuric acid was added with a mass fraction of 5% of excess barium nitrate solution, a precipitate weighing 23.3 grams was formed. Find the mass of sulfuric acid.

Let’s determine the chemical amount of synthesized barium sulfate.

To do this, we divide its weight by its molar mass, equal to the sum of the molar weights of the atoms included in the molecule.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

N BaSO4 = 23.3 / 233 = 0.1 mol;

To synthesize 0.1 mol of barium sulfate, you must take at least 0.1 mol of sulfuric acid.

Let’s find its weight. For this purpose, we multiply its chemical amount by its molar mass.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

m H2SO4 = 0.1 x 98 = 9.8 grams;

The mass of the solution with this amount of sulfuric acid will be: 9.8 / 0.05 = 196 grams;