When the body was lowered into a beaker of water, part of it sank. The water level rose from

When the body was lowered into a beaker of water, part of it sank. The water level rose from the 20cm3 mark to the 120cm3 mark. What is the body weight?

g = 9.8 m / s ^ 2.

ρ = 1000 kg / m ^ 3.

V1 = 20 cm ^ 3 = 20 * 10 ^ -6 m ^ 3.

V2 = 120 cm ^ 3 = 120 * 10 ^ -6 m ^ 3.

m -?

Two forces act on a body immersed in water: the force of gravity Ft directed vertically downward, and the buoyancy force of Archimedes Farkh, directed vertically upward.

The force of gravity is determined by the formula: Ft = m * g, where m is the mass of the body, g is the acceleration of gravity.

The buoyancy force of Archimedes is determined by the formula: Farch = ρ * g * V. Where ρ is the density of the liquid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed part of the body in the liquid.

m * g = ρ * g * V.

m = ρ * V.

The volume of the submerged part of the body V is found by the formula: V = V2 – V1.

m = ρ * (V2 – V1).

m = 1000 kg / m ^ 3 * (120 * 10 ^ -6 m ^ 3 – 20 * 10 ^ -6 m ^ 3) = 0.1 kg.

Answer: the mass of the submerged body is m = 0.1 kg.