When the capacitor was charged with 5 * 10 ^ -6 cells, its energy turned out to be 0.01 J. determine the voltage of the capacitors.

To determine the voltage across the capacitor taken, we apply the formula: W = q * U / 2, whence U = 2 * W / q.

Value of variables: W – capacitor energy (W = 0.01 J); q is the charge transferred to the capacitor (q = 5 * 10-6 C).

Let’s make a calculation: U = 2 * W / q = 2 * 0.01 / (5 * 10-6) = 4 * 10 ^ 3 V or 4 kV.

Answer: The voltage across the capacitor taken is 4 kV.