When the car was moving at a speed of 72 km / h, the engine developed a traction force

When the car was moving at a speed of 72 km / h, the engine developed a traction force of 6000 N. What work did the engine do on the 4 km path?

Given: V (constant speed of the vehicle under consideration) = 72 km / h (in the SI system V = 20 m / s); F (engine thrust force) = 6000 N; S (distance traveled) = 4 km (in SI S = 4 * 10 ^ 3 m).

The work done by the car in question on its way is calculated by the formula: A = F * S.

Let’s perform the calculation: A = 6000 * 4 * 10 ^ 3 = 24 * 10 ^ 6 J (24 MJ).

Answer: The engine of the car on the traversed path performed work at 24 MJ.