When the copper rod was cooled by 25 degrees, 22 J of energy was released. What is the mass of the copper rod?

Data: Δt (change in temperature of the taken copper rod) = 25 ºС; Q (released thermal energy) = 22 J.

Constants: Cm (specific heat of copper) = 400 J / (kg * K).

To find the mass of the taken copper rod, we apply the formula: Q = Cm * m * Δt, whence m = Q / (Cm * Δt).

Calculation: m = 22 / (400 * 25) = 0.0022 kg or 2.2 g.

Answer: The mass of the taken copper rod is 2.2 g.



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