When the current in the inductor changes by 1A for 0.5 s, an EMF of 0.2 mV is injected into it.

When the current in the inductor changes by 1A for 0.5 s, an EMF of 0.2 mV is injected into it. What wavelength will the radio wave have if the circuit consists of this coil and a 50μF capacitor?

Given:
I = 1 A;
t = 0.5 s;
EMF = 0.2 mV.
Find: ∧ – length.
Decision:
First, we find the strength of the electric field. For this, we use this formula: E = 0.2 * 10 ^ -3 B.
Next, we write down what the delta of the current strength is. Delta I = 1 A.
Further, similarly, we will write down what the time delta is. Delta t = 0.5c.
Then we find C. C = 50 * 10 ^ -6 F.
We know that c = 3 * 10 ^ 8 m / s.
Now we have all the data to find the length using the formula. Let’s write it down. ∧ = c * T.
However, we do not know the value of T. We find it by the formula T = 2 * n * root of (L * C). In this formula, we do not know the value of L. However, we have the value of all variables in order to find it by the formula: L = E * Δt / ΔI.
Substitute the right side of this equation into the length formula and calculate the answer.
∧ = 2 * n * c * root of (E * Δt * C / ΔI) = 2 * 3.14 * 3 * 10 ^ 8 * root of (0.2 * 10 ^ -3 * 0.5 * 50 * 10 ^ -6 / 1) = 132 * 10 ^ 3 m.
Answer: 132 * 10 ^ 3 m