When the door was opened, the length of the door spring increased by 12 cm
| September 29, 2021 | education
When the door was opened, the length of the door spring increased by 12 cm, while the elastic force became equal to 4n which is equal to the stiffness of the spring.
Data: Δx (increase in the length of the door spring) = 12 cm (in SI Δx = 0.12 m); Fel (emerged elastic force) = 4 N.
To calculate the cruelty of the door spring, we apply Hooke’s law: Fupr. = | k * Δх | and k = Fcont. / Δх.
Calculation: k = 4 / 0.12 = 33.33 N / m.
Answer: The stiffness of the door spring is 33.33 N / m.
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