When the frequency of the voltage change of the current source included in the
| September 30, 2021 | education
When the frequency of the voltage change of the current source included in the oscillatory circuit is equal to 50 Hz, resonance is observed. What is in this case the inductance of the coil of the oscillating circuit, if the capacitance of the capacitor is 2.6 • 10 (in – 8 degrees) Ф?
Solution:
T = 1/50 = 0.02 s
0.02 = 2 * 3.14 * √LC
LC = 0.00010142
2.6L = 10142
L = 3900.8 H
Answer: 3900.8 Gn
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