When the gas is heated by 18 K, its volume increases by 6%. What is the initial air temperature?

Given: ΔT (change in temperature of the taken gas during heating) = 18 K; ΔV / V (increase in gas volume) = 6% = 0.06; the taken gas pressure will be considered constant.

The initial temperature of the taken gas is determined from the equality: V / T = const = (V + ΔV) / (T + ΔT), whence V * (T + ΔT) = (V + ΔV) * T.

V * T + V * ΔT = V * T + ΔV * T.

V * ΔT = ΔV * T.

T = V * ΔT / ΔV.

Let’s make a calculation: T = 18 / 0.06 = 300 K.

Answer: The initial temperature of the taken gas was 300 K.