When the lever is in balance, a force of 60N acts on its larger arm, equal to 80cm

When the lever is in balance, a force of 60N acts on its larger arm, equal to 80cm, and a force of 240N acts on the smaller one. Define a smaller shoulder.

These tasks: the lever used is in equilibrium; lb (the length of the larger arm) = 80 cm (in the SI system lb = 0.8 m); Fb (force applied to the larger arm) = 60 N; Fm (force applied to the smaller arm) = 240 N.

To calculate the length of the smaller lever arm, we apply the equality: Fb * lb = M = Fm * lm, whence lm = Fb * lb / Fm.

Calculation: lm = 60 * 0.8 / 240 = 0.2 m.

Answer: The desired length of the smaller arm of the used lever is 0.2 m.