When the lever is in equilibrium, a force of 100 N acts on its smaller arm, and a load weighing 500 g

When the lever is in equilibrium, a force of 100 N acts on its smaller arm, and a load weighing 500 g is on the larger arm. The smaller shoulder length is 2.5cm. Determine the length of your larger shoulder.

Data: equilibrium position of the lever; Fm (force on the smaller arm) = 100 N; m (weight of the load on the larger shoulder) = 500 g (in SI m = 0.5 kg); lm (length of the smaller arm) = 2.5 cm (in SI lm = 0.025 m).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To calculate the length of the larger arm of the taken lever, we use the equality: M = Fb * lb = Fm * lm and lb = Fm * lm / Fb = Fm * lm / (m * g).

Calculation: lb = 100 * 0.025 / (0.5 * 10) = 0.5 m.

Answer: The larger shoulder is 0.5 m long.