When the spring is compressed by 2 cm, an elastic force is generated equal to 72 N. How much must the spring

When the spring is compressed by 2 cm, an elastic force is generated equal to 72 N. How much must the spring be compressed relative to the equilibrium position for an elastic force equal to 108 N to arise?

Given: Δx1 (initial compression) = 2 cm; Fupr1 (initial elastic force) = 72 N; Fel2 (considered elastic force) = 108 N.

SI system: Δx1 = 0.02 m.

To find the required deformation of the taken spring, apply the proportion: Fcont1 / Δx1 = Fcont2 / Δx2, whence Δx2 = Fcont2 * Δx1 / Fcont1.

Solution: Δx2 = 108 * 0.02 / 72 = 0.03 m or 3 cm.

Answer: With respect to the equilibrium position, the taken spring must be compressed by 3 cm.