When the spring is lengthened by 1 cm, an elastic force of 10 N occurs. What is the stiffness of the spring?
| August 6, 2021 | education
Initial data: Fel (elastic force, which arose when the spring was lengthened) = 10 N; Δl (the amount of deformation of the spring, its elongation) = 1 cm.
SI system: Δl = 1 cm = 0.01 m.
The stiffness of the spring can be determined by calculating the ratio of the elastic force to the elongation of the spring: k = Fel / Δl.
Calculation: k = 10 / 0.01 = 1000 N / m.
Answer: The spring rate will be 1000 N / m.
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