When the spring is stretched by 2 cm, an elastic force of 20 N appears. What is the spring stiffness?
| December 31, 2020 | education
Given:
dL = 2 cm = 0.02 m – the amount of tension of the spring
Fel = 20 N – elastic force
Decision:
k = Fcont / dL – formula for the spring stiffness according to Hooke’s law
k = Fcont / dL = 20 / 0.02 = 1000 N / m
Answer: k = 1000 N / m – spring rate
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