When the spring is stretched by 6 cm, an elastic force is generated in it equal to 300 N. What is the stiffness of the spring?
| September 11, 2021 | education
To calculate the stiffness of the taken spring, we apply Hooke’s law: Fcont. = k * Δx and k = Fcont. / Δx.
Variable values: Fcont. – the force of elasticity arising in the taken spring (Fel. = 300 N); Δx – spring deformation (Δx = 6 cm; in SI Δx = 0.06 m).
Let’s make a calculation: k = Fcont. / Δx = 300 / 0.06 = 5000 N / m or 5 kN / m.
Answer: The stiffness coefficient is 5 kN / m.
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