When the voltage between the ends of the circuit section is 5 V, the current strength is 0.8 A.

| March 9, 2021 | education

When the voltage between the ends of the circuit section is 5 V, the current strength is 0.8 A. Calculate the current strength in this section of the circuit when the voltage increases by 4 times.

The current, voltage and resistances of the circuit section are related according to Ohm’s law, the formula of which is as follows:
I = U / R, where I- current, U- voltage, R- resistance

From this ratio, you can get a formula for calculating the resistance.
R = U / I
R = 5 [V] / 0.8 [A] = 6.25 [Ohm]

The voltage was increased 4 times, which means it became:
5 [V] * 4 = 20 [V]

Then the current through the section of the circuit with a resistance of 6.25 [Ohm] and a voltage of 20 [V] is equal to:
I = U / R = 20 [V] / 6.25 [Ohm] = 3.2 [A]

Answer: the current strength is 3.2 [A]



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