When transferring 60 sts of electricity from one point of the electrical circuit to another in 12 minutes

When transferring 60 sts of electricity from one point of the electrical circuit to another in 12 minutes, a work of 900 J. was performed. Determine the voltage and current in the circuit.

Task data: q (value of the transferred charge) = 60 C; t (charge transfer time) = 12 min (in SI t = 720 s); A (perfect work) = 900 J.

1) Determine the voltage in the electrical circuit: U = A / q = 900/60 = 15 V.

2) Let’s calculate the current strength: I = q / t = 60/720 = 0.0833 A.

3) Let’s check (Joule-Lenz law): A = Q = U * I * t = 15 * 0.0833 * 720 = 900 J (correct).

Answer: The voltage in the circuit is 15V; the current strength is 0.0833 A.