When transferring a 2nC charge from one point to another, the electric field did the work
| March 12, 2021 | education
When transferring a 2nC charge from one point to another, the electric field did the work of 15mkJ. What is the potential difference between these points?
Data: q (value of the transferred charge) = 2 nC (2 * 10-9 C); A (work done by the field) = 15 μJ (15 * 10-6 J).
To calculate the value of the potential difference between the given points, we apply the formula: φ1 – φ2 = A / q.
Calculation: φ1 – φ2 = 15 * 10-6 / (2 * 10-9) = 7500 V (7.5 kV).
Answer: The potential difference between the points is 7.5 kV.
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