When transferring the amount of heat 25kJ to the gas, it performed work of 35 kJ. What is the change in the internal

When transferring the amount of heat 25kJ to the gas, it performed work of 35 kJ. What is the change in the internal energy of the gas? Gas has cooled or heated

Q = 25 * 10 ^ 3 (J)
A (gas) = 35 * 10 ^ 3 (J)
A ‘= A (gas) = – 35 * 10 ^ 3 (J)
ΔU = Q + A ‘
ΔU = 25 * 10 ^ 3 – 35 * 30 ^ 3 = – 10 * 30 ^ 3 (J)
The value is negative, which means that the internal energy of the gas has decreased.
Answer: decreased by 10 * 30 ^ 3 (J)



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