When transferring to a steel rod with a mass of 250 g, the amount of heat is 8 kJ

When transferring to a steel rod with a mass of 250 g, the amount of heat is 8 kJ, it heats up to a temperature of 80 ° C. Determine the starting temperature of the rod.

We calculate the initial temperature of the rod from the formula:

Q = C * m * (t2 – t1), where Q is the consumed heat (Q = 8 kJ or 8000 J), C is the specific heat capacity of steel (table value C1 = 500 J / (K * kg)), m – the mass of the rod (m = 250 g or 0.25 kg), t2 is the temperature of the rod after heating (t2 = 80 ° C), t1 is the desired temperature of the rod before heating.

t2 – t1 = Q / (C * m).

t1 = t2 – Q / (C * m).

Payment:

t1 = 80 – 8000 / (500 * 0.25) = 80 – 64 = 16 ° C.

Answer: The initial temperature of the steel bar is 16 ° C.



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